Final 6 - Balloon Balance

Given:

• $\mbox{In an electrical field of 10,000 N/C, a mass of 30 grams is charged.} $

Question:

• $\mbox{How large must that charge be to suspend the mass neither moving up nor down?} $

Rationale:

• $F_{gravity} = F{electrical} $
• $m a = E q   $
• $q = \dfrac{m a}{E}   $

Calculate:

• $q = \dfrac{(30 * 10^{-3}) (10)}{10^4} = 3 * 10^{-5} $

References:

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