Tuesday, August 7, 2012

Final 9 - Strange Planet


Given:

  • $\mbox{Length of pendulum is 12 meters and it took 45 seconds for it to swing back and forth.} $

Question:

  • $\mbox{What is the force of gravity on this planet?} $

Rationale:

  • $T = 2 \pi \sqrt{\dfrac{l}{g}} $

Calculate:

  • $\dfrac{45}{10} = (2) \dfrac{22}{7} \sqrt{\dfrac{12}{g}} $
    • $  (4.5) \dfrac{7}{44} = \sqrt{\dfrac{12}{g}} $
    • $ 0.71590 = \sqrt{\dfrac{12}{g}} $
    • $ 0.51251281 = \dfrac{12}{g}  $
    • $ g = \dfrac{12}{ 0.51251281} = 23.4140489 \approx 23.4 $

References:

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