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Monday, July 16, 2012

Unit 4 - Problem 1 ==> Rollercoaster Design

Given

  • A rollercoaster car with mass m at height h goes into a loop.
  • At the top of the loop of radius r the car must go a velocity of V to be safe
  • What is the minimum height the car must start at?

Rationale

  • E_{potential} = E_{top-of-loop} + E_{kinetic-top-of-loop}
  • m_{car} a_{gravity} h_x = (m_{car} a_{gravity} h_{top-of-loop}) + (\frac{1}{2} m_{car} V^2_{top-of-loop})
  • a_{gravity} h_x = (a_{gravity} h_{top-of-loop}) + (\frac{1}{2} V^2_{top-of-loop})

Calculations

  • 10h_x = (10*20) + (\frac{1}{2}*10^2)
  • 10h_x = 200 + 50 = 250
  • h_x = 25

Height vs Loop Radius

  • Derivation from MIT Professor Lewin at about 28:40 on the video.
  • At any point along the track, mgh = mgy + \frac{1}{2}m v^2
  • Which simplifies to, 2g (h-y) = V^2
  • At the lop of the loop, y = 2r
  • From previous work, at the apex of the loop,  a_{centripetal} = g = \frac{V^2}{R}
  • V^2 = g * R
  • Therefore, 2g*(h-2r) \ge g*r
  • 2h - 4r \ge r
  • h  \ge \frac{5}{2} r
  • Regardless of mass of object, for it to stay on the track, it must originate from a height of at least 2.5 times the radius of the loop.

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