Unit 6 - Problem 7 ==> Fields and Angles

Given:

• $$ q_1, q_2, \theta_1, \theta_2 $$

Rationale:

• $$ \tan\theta_1 = \frac{E * q_1}{F_{both}}  $$
• $$ F_{both} = \frac{E * q_1}{\tan\theta_1}  $$
• $$ \tan\theta_2 = \frac{-E * q_2}{-F_{both}}  $$ 
• $$ F_{both} = \frac{E * q_2}{\tan\theta_2}  $$
• $$ F_{both} = F_{both} $$
• $$ \frac{E * q_1}{\tan\theta_1}= \frac{E * q_2}{\tan\theta_2}  $$
• $$ \frac{q_1}{q_2} = \frac{\tan\theta_1}{\tan\theta_2} $$

Calculate

• $$ \frac{q_1}{q_2} = \frac{\tan{76}^\circ}{\tan{24}^\circ} $$
• $$ \frac{q_1}{q_2} = \frac{4.01078}{.445229}  = 9.0 $$