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Tuesday, August 7, 2012

Final 15 - Gravity and Electricy


Given:

  • \mbox{A mass of 8 kg and a charge of 0.1 coulombs}
    • \mbox{Is dropped from a height of 1.2 meters}
    • \mbox{In the continuing presence of an  electric field of 100 newtons/coulomb.}

Question:

  • \mbox{What distance d does the mass hit the floor?}

Rationale:

  • \Delta{y} = 0.5 g t^2
    • t^2 = \dfrac{2 \Delta{y} }{g}
  • F_{electric} = F_x = m a_x
    • E q =  m a_x
    • a_x = \dfrac{(E q)}{m}
  • t_y^2 = t_x^2
  • \Delta{x} = .5 (\dfrac{(E q)}{m})  \dfrac{2 \Delta{y} }{g}

Calculate:

  • \Delta{x} = .5 (\dfrac{(100 * .1)}{8})  \dfrac{2 * 1.2 }{10} = 0.15 \; \mbox{meters} 

References:

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