Final 15 - Gravity and Electricy

Given:

• $\mbox{A mass of 8 kg and a charge of 0.1 coulombs}$
• $\mbox{Is dropped from a height of 1.2 meters}$
• $\mbox{In the continuing presence of an  electric field of 100 newtons/coulomb.} $

Question:

• $\mbox{What distance d does the mass hit the floor?} $

Rationale:

• $\Delta{y} = 0.5 g t^2 $
• $ t^2 = \dfrac{2 \Delta{y} }{g} $
• $F_{electric} = F_x = m a_x $
• $E q =  m a_x $
• $a_x = \dfrac{(E q)}{m} $
• $t_y^2 = t_x^2 $
• $\Delta{x} = .5 (\dfrac{(E q)}{m})  \dfrac{2 \Delta{y} }{g} $

Calculate:

• $\Delta{x} = .5 (\dfrac{(100 * .1)}{8})  \dfrac{2 * 1.2 }{10} = 0.15 \; \mbox{meters}$ 

References:

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