Final 6 - Balloon Balance

Given:

• $\mbox{In an electrical field of 10,000 N/C, a mass of 30 grams is charged.}$

Question:

• $\mbox{How large must that charge be to suspend the mass neither moving up nor down?}$

Rationale:

• $F_{gravity} = F{electrical}$
• $m a = E q$
• $q = \dfrac{m a}{E}$

Calculate:

• $q = \dfrac{(30 * 10^{-3}) (10)}{10^4} = 3 * 10^{-5}$

References: