Final 8 - Cable Car Power

Given:

• $\mbox{A 2,000 kg cable car on an alpha 10 degree slope.}$

Question:

• $\mbox{How much power does it take to move the trolley at 25 km/hour?}$

Rationale:

• $25 \dfrac{km}{hour} = 25 \dfrac{1000 \mbox{meters-per-km}}{3600 \mbox{seconds-per-hour}}$
•  $25 \dfrac{km}{hour} =6.944444 \; \mbox{meters per second}$
• $P = F_{parallel} V = m g \sin\alpha V$

Calculate:

• $P = (2000) (10) (.173648178) (6.9444) = 24,117.648146$
•  $P = \approx 24,117$

References: