Unit 5 - Problem 4 ==> Shock Absorber Damping

Given:

• 20.6% of energy lost per cycle of shock absorber
• $$E_n = (1 - .206)^n E_0  = (0.794)^n E_0$$
• $$E \varpropto A^2$$

Rationale:

• $$ (.5 A)^2 \varpropto E
• $$(0.794)^n = .5^2 = .25$$

Calculate:

• Powers of 0.794
• $$0.794 ^2 = 0.630436$$
• $$0.794 ^3 = 0.500566$$
• $$0.794 ^4 = 0.397449$$
• $$0.794 ^5 = 0.315574$$
• $$0.794 ^6 = 0.250566$$
• n = 6