Unit 5 - Problem 4 ==> Shock Absorber Damping

Given:

• 20.6% of energy lost per cycle of shock absorber
• $$ E_n = (1 - .206)^n E_0  = (0.794)^n E_0 $$
• $$ E \varpropto A^2 $$

Rationale:

• $$ (.5 A)^2 \varpropto E
• $$ (0.794)^n = .5^2 = .25 $$

Calculate:

• Powers of 0.794
• $$ 0.794 ^2 = 0.630436 $$
• $$ 0.794 ^3 = 0.500566$$
• $$ 0.794 ^4 = 0.397449 $$
• $$ 0.794 ^5 = 0.315574 $$
• $$ 0.794 ^6 = 0.250566 $$
• n = 6