I am taking the basic physics class thru Udacity. This blog is my scratch pad and results as I work my way thru the class. In addition, I am refreshing myself on basic calculus
Monday, July 30, 2012
Unit 6 - Problem 2 ==> Parallel Plates
Given:
E_{field} = 1000
d = 1 \; \mbox{cm}
m_{proton} = 1.673 * 10^{-27}
q = 1.6024 * 10^{-19}
\mbox{Initial velocity of charge}\; = 0
Question:
\mbox{How long, in nanoseconds, does it take the proton to cross between the two plates?}
Overview of Approach:
Convert centimeters to meters for final calculations
Determine force on charge due to electrical field
Determine acceleration on charge due to force on charge
Determine time to transit using the acceleration
Rationale:
Convert centimeters to meters
1 \; \mbox{cm} = 1 * 10^{-2} \; \mbox{meters}
Determine force on charge due to electrical field
E = \frac{F_e}{q}
F_e = E * q
Determine acceleration on charge due to force on charge
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