Unit 4 - Problem 2 ==> Rollercoaster with friction
Given
- Similar to Unit 4 - Problem 2
- Initial height = 45 meters
- There is a 20 meter section before the loop that creates a friction force.
- What is maximum value of friction force?
Rationale
- $$E_{potential} = E_{top-of-loop} + E_{kinetic-top-of-loop}$$
- $$m_{car} a_{gravity} h = (m_{car} a_{gravity} h_{top-of-loop}) + (\frac{1}{2} m_{car} V^2_{top-of-loop}) - (F_{x-friction-max} d_{bad-track}) $$
Calculations
- $$(200*45*10) = (200*20*10) + (\frac{1}{2}*200*10^2) - (F_{x-friction-max}*20)$$
- $$90000 = 40000 + 10000 - (F_{x-friction-max}*20) $$
- $$90000 - 50000 = -20F_{x-friction-max}$$
- $$40000 = -20F_{x-friction-max}$$
- $$F_{x-friction} = -2000 $$
No comments:
Post a Comment