Unit 6 - Problem 7 ==> Fields and Angles

Given:

• $$q_1, q_2, \theta_1, \theta_2$$

Rationale:

• $$\tan\theta_1 = \frac{E * q_1}{F_{both}}$$
• $$F_{both} = \frac{E * q_1}{\tan\theta_1}$$
• $$\tan\theta_2 = \frac{-E * q_2}{-F_{both}}$$  
• $$F_{both} = \frac{E * q_2}{\tan\theta_2}$$
• $$F_{both} = F_{both}$$
• $$\frac{E * q_1}{\tan\theta_1}= \frac{E * q_2}{\tan\theta_2}$$
• $$\frac{q_1}{q_2} = \frac{\tan\theta_1}{\tan\theta_2}$$

Calculate

• $$\frac{q_1}{q_2} = \frac{\tan{76}^\circ}{\tan{24}^\circ}$$
• $$\frac{q_1}{q_2} = \frac{4.01078}{.445229}  = 9.0$$